Source Code
#include <iostream>
#include <math.h>
using namespace std;

int main() {
 long double n, k, l;

 cin >> n >> k >> l;

 long double ans= n/((1/k)+(1/l));

 printf("%.0Lf",ceil(ans));


}
Copy
Hurry up zeina.k
GNU G++17
0 ms
600 KB
Wrong Answer