Source Code
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//using namespace __gnu_pbds;
using namespace std;
/* #pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")*/
typedef  unsigned long long ll;
const ll MAXN = 1e5 + 2;
const ll MAXK = 5e2 + 2;
const ll MOD = 1e9 + 7;
const ll MODH = 1e9 + 9;
const int MAXLG = 20;
const long double PI = acos(-1);
const ll sp = 41;
const long double EPS = 1e-4;
//mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
//inline ll rand(ll a, ll b) {ll c = rng(); return a+((ll)abs(c))%(b-a+1);}
//ll binpow(ll a, ll b, ll m) {a %= m;ll res = 1;while (b > 0) {if (b & 1){res = res * a % m;}a = a * a % m;b >>= 1;
//}return res;}
 
 


 
int main() {
 

int n;
ll k;
cin >> n >> k;
ll all = 0;
vector<int> a(n);
for(int i = 0 ; i < n ; i++){
	 cin >> a[i];
     all+=a[i];
	}


ll lo = 0 , hi = 1e9;
ll iter = 0;
while(lo <= hi)
{
	ll mid = (lo + hi) / 2;

	ll sum = mid * (mid + 1) / 2;

	if(sum > k/all)
	{
		hi = mid - 1;
	}
	else
	{
		iter = mid;
		lo = mid + 1;
	}

}


ll Ans = iter * n;
k-=((iter  * (iter + 1) / 2) * all);

if(iter & 1)
	 reverse(a.begin(),a.end());

for(int i = 0 ; i < n ; i++)
{
	ll cost = (iter + 1) * a[i];
	if( cost <= k)
	{
		Ans++;
		k-=cost;
	}
	else
		break;
}


cout << Ans;

 
}
Copy
Saqqa 26/40 DoeJohn
GNU G++17
24 ms
1.4 MB
Wrong Answer